[bldg-sim] question about customed chiller curve
Gary Zeng
gzeng at royalservice.com
Mon Apr 4 03:20:09 PDT 2005
Dear guys:
Sorry for take your time again.
Now we are working on a project in which we need to custom the chiller curve
for both screwed chiller and the hermetic centrifugal one.
As i searched the Doe manual and the help files, the instruction suad that
we can do this by input the raw data of chiller part load conditions. It
works, but I still have some problems.
1 in the EIR-CHWT/ECT curve, what is the CHWT and ECT exactly mean?
Are they the leaving chillered water temperature and entering condensing
temperature?
2 in the EIR-PLR/dT cueve,what is the delta temperature, or in other words,
which two temperatures is used here to get the delta T.
3 i would like to know if there are any examples on how to do this,
I attched my personnal curve here for your reference. By the way, the space
cooling energy is a little big when using my curve compared with the ones
from the lib. In my case, i applied all of my three personal curve.
"tr-cap-fchwt&ect" = CURVE-FIT
TYPE = BI-QUADRATIC-T
INPUT-TYPE = DATA
INDEPENDENT-1 = ( 44.6, 44.6, 44.6, 44.6, 44.6, 44.6, 44.6, 44.6 )
INDEPENDENT-2 = ( 89.6, 84.69, 79.75, 74.84, 69.93, 64.99, 64.99, 64.99
)
DEPENDENT = ( 1, 0.9, 0.8, 0.7, 0.6, 0.5, 0.4, 0.3 )
..
"tr-eir-fchwt&ect" = CURVE-FIT
TYPE = BI-QUADRATIC-T
INPUT-TYPE = DATA
INDEPENDENT-1 = ( 44.6, 44.6, 44.6, 44.6, 44.6, 44.6, 44.6, 44.6 )
INDEPENDENT-2 = ( 89.6, 84.69, 79.75, 74.84, 69.926, 64.99, 64.99,
64.99 )
DEPENDENT = ( 1, 0.926, 0.869, 0.822, 0.742, 0.68, 0.85, 1.05 )
..
"tr-" = CURVE-FIT
TYPE = BI-QUADRATIC-RATIO&DT
INPUT-TYPE = DATA
INDEPENDENT-1 = ( 1, 0.9, 0.8, 0.7, 0.6, 0.5, 0.4, 0.3 )
INDEPENDENT-2 = ( 45, 40.086, 35.154, 30.24, 25.326, 20.394, 20.394,
20.394 )
DEPENDENT = ( 1, 0.926, 0.869, 0.822, 0.742, 0.68, 0.85, 1.05 )
..
Your reply and youe help will be greatly appreciated.
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