[Equest-users] Steam loop pumping energy

[Jay Keazer]

Here is another way to deal with this issue:

 

·         Create a linear curve fit with coefficients of 

o    a = 0

o    b = 0

 

·         Assign this curve to Pump keyword "Pump Power f(flow)".  You don't
need to change any other pump parameters.  Check Report PS-C to see that the
KWH is 0.

 

 

Jay Keazer, EI

Energy Engineer

TME, Inc.

2039 N Green Acres Road

Fayetteville, AR  72703

 

ph   479.521.8634

fax  479.521.1014

cell  479.xxx.xxxx

email at tmecorp.com

 

 

 

 

From: equest-users-bounces at lists.onebuilding.org
[mailto:equest-users-bounces at lists.onebuilding.org] On Behalf Of Jack Manning
Sent: Tuesday, October 14, 2008 7:08 PM
To: Steven Savich
Cc: equest-users at lists.onebuilding.org
Subject: Spam:Re: [Equest-users] Steam loop pumping energy

 

Steven

 

I would not try and eliminate pumping power all together. 

To minimise reduce pressure to a low level, apply good mech efficiency so not
much heat is added to the loop by the pump.

Then at the end of the process simply do not include pumping energy in your
results (i.e. working with totals, subtract the heating water pump energy
from the total energy use).

These values can be taken from the sim file. Or the approach I would take is
to get an hourly or monthly output file for the all parameters you wish to
monitor.

 

Cheers

Jack

 

Jack Manning

Mechanical Engineer

MEP - Sustainable Design

 

Arup

Level 10, 201 Kent Street, Sydney NSW 2000

T  +61 (0)2 9320 9634

F  +61 (0)2 9320 9321

M +61 (0)434 399 543

www.arup.com <http://www.arup.com/> 

 

We shape a better world

 

From: equest-users-bounces at lists.onebuilding.org
[mailto:equest-users-bounces at lists.onebuilding.org] On Behalf Of Xavier
García Casals
Sent: Wednesday, 15 October 2008 3:32 AM
To: Steven Savich
Cc: equest-users at lists.onebuilding.org
Subject: Re: [Equest-users] Steam loop pumping energy

 

Steven,
The program will calculate one of the pump input parameters acording to the
relationship between power, efficiency, head and flow. Try assigning an
almost 0 kW power, and leave another parameter free (for example head) for
the programe to use the formula to calculate this parameter instead of
overriding the almost 0 kW power.

En/na Steven Savich ha escrit: 

David,

 

Tried that.  The program ignores the 0 pump power input and calculates the
required power, even with actual flow and head input.  PS-C report still
shows pump energy consumption by the heating water loop pump.

 

FYI I'm using eQuest ver 3-61e.  Do later or earlier versions allow this 0 kW
workaround?

 

Steven

 

Steven Savich

Systems West Engineers

411 High Street

Eugene, OR  97401-2427

(541) 342-7210

(541) 342-7220 (fax)

________________________________

From: David S Eldridge [mailto:DSE at grummanbutkus.com] 
Sent: Tuesday, October 14, 2008 9:09 AM
To: 'Steven Savich'
Subject: RE: [Equest-users] Steam loop pumping energy

 

You can use the actual flow and head so the program doesn't crash, but enter
a pump power of 0 kW.  "Magic" pump motors.

 

From: equest-users-bounces at lists.onebuilding.org
[mailto:equest-users-bounces at lists.onebuilding.org] On Behalf Of Steven
Savich
Sent: Tuesday, October 14, 2008 10:52 AM
To: equest-users at lists.onebuilding.org
Subject: [Equest-users] Steam loop pumping energy

 

All,

 

I'm modeling a university campus building with heat provided by central plant
steam boilers, providing 15# steam.  I've done this by eliminating boilers in
the model and attaching a steam meter to the hot water loop.

 

My problem is with pumping energy.  Equest requires that a pump be attached
to the hot water loop, but the actual installation has gravity return
condensate.  How do I zero out the pumping energy?  I have set pump head = 0,
but this gives me pages of error reports.  Any other methods?

 

Thanks,

Steven

 

Steven Savich

Systems West Engineers

411 High Street

Eugene, OR  97401-2427

(541) 342-7210

(541) 342-7220 (fax)

 

 
 
 



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-- 

 
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