[Bldg-sim] Why should roofs have high emissivity?

[Shawn.Lee at fluor.com]

Good Job, Charlie,

The distinction between Solar and Thermal Bands and the variation of the 
properties of the material along the wavelengths are the key to settle 
this aperient contradiction. 

Thank you, Charlie.

Shawn Lee
PhD, PE
 




"D. Charlie Curcija" <curcija at designbuildersoftware.com>
Sent by:  bldg-sim-bounces at lists.onebuilding.org
11/30/2009 07:35 AM

To
<muehleisen at iit.edu>, "'Brad Painting'" <bradpainting at gmail.com>
cc
bldg-sim at lists.onebuilding.org
Subject
Re: [Bldg-sim] Why should roofs have high emissivity?








Whoa, just a moment!  This discussion is starting to deteriorate into half
truths and inaccuracies.  First of all, most common (and inexpensive) 
paints
satisfy criteria of having high solar reflectance and high thermal
emissivity.  Ordinary white paint meets this criteria and for that reason 
is
very applicable for cool roofs.  The key here is that there are two major
bands of radiation, Solar (encompassing roughly UV, visible and near
infra-red wavelengths - from around 0.38 microns to 2.5 microns) and far
infra-red (also known as thermal) band (from about 2.5 microns to 50
microns).  Sun, with "surface" temperature of around 9300 F emits 
radiation
in, well Solar band, hence the name of the band.  Absorbed radiation in a
roof surface emits radiation energy in thermal band, because its 
temperature
is 100-200 F, which is much less than 9300 F.  Thus, surface properties 
need
to be evaluated at these two major bands.

Kirchoff's Law states that emissivity and absortivity of a surface is same
at the same wavelength, so if we slightly extrapolate this principle to 
the
entire band (not quite true but good enough for understanding the 
problem),
than one can say emissivity and absorptivity at solar band are equal and
emissivity and absorptivity at thermal band are equal.  While color of
paints affects solar absorptivity (thus white paint is reflective while
black paint is absorptive), all of these colors have same or nearly the 
same
emissivity at the thermal band (0.9).  This gives simple and inexpensive
solution to cool roof problem.  Paint the roof with white paint or other
light color, keep it relatively clean (because dirt will increase solar
absorptivity of the surface) and you got the cool roof.

Observation from several posters that high emissivity of the surface helps
in cooling climates is correct, meaning that high thermal emissivity of 
the
roof surface will help dissipate absorbed solar energy, since the
temperature to which roof is radiating in thermal band (sky, surrounding
objects) is quite a bit lower than the roof temperature.

Charlie Curcija
DesignBuilder Software

-----Original Message-----
From: bldg-sim-bounces at lists.onebuilding.org
[mailto:bldg-sim-bounces at lists.onebuilding.org] On Behalf Of Ralph
Muehleisen
Sent: Sunday, November 29, 2009 10:34 PM
To: Brad Painting
Cc: bldg-sim at lists.onebuilding.org
Subject: Re: [Bldg-sim] Why should roofs have high emissivity?

Brad,

The emissivity and absorptivity of a passive material at any given
wavelength are equal, as stipulated by Kirchhoff over 100 years ago.
The only materials that violate this law are phase change materials
(which only violate it in a time average sense) or materials that have
some funky quantum mechanical mechanisms for heat removal.

Most common building materials have a similar absorpitivity (and
emissivity) for both short wavelengths (visible light i.e. solar
energy) and long wavelengths (infrared).  It is quite possible however
to design materials with a different absorptivity=emissivity for short
wavelengths and long wavelengths.  This is what makes a so-called
"cool" roof.

If you write a simple spreadsheet to compute the temperature on a roof
using an energy balance you can show that for a standard roof (i.e.
absorptivity=emissivity about the same at all wavelengths) the lowest
roof temperature and therefore lowest heat gain to the building will
be at a roof for a low absorptivity=low emissivity.

As important (or perhaps more important) in the overall roof design is
controlling the roof surface temperatures.  High temperatures mean
that the rooftop will undergo large temperature swings which means
large expansion/contraction and more thermal stress on the roof.  High
roof temperatures also mean locally high air temperatures which means
any rooftop condensers will have decreased efficiency.

A high absorptivity black roof can truly get hot enough to boil water
or fry eggs (210+ degrees F) on a hot summer day without wind
throughout much of the US.  An aluminum roof on the other hand might
get up to 160 F.

I've got an excel spreadsheet that I use in my building enclosure
design class that does the heat balance calculation and will show you
the heat transfer from solar insolation, long wavelength radiation
exchange to the sky, convection to the sky and conduction to the
interior.
Anyone who wants a copy can email me and I'll email it back to them.

Ralph

Ralph Muehleisen, Ph.D., P.E., LEED AP, FASA
Assistant Professor and Director of the Miller Acoustics Lab
Civil, Architectural and Environmental Engineering
Illinois Institute of Technology
Chicago, IL 60616
muehleisen at iit.edu
tel: 312-567-3545  fax:312-567-3519



On Sun, Nov 29, 2009 at 2:57 PM, Brad Painting <bradpainting at gmail.com>
wrote:
> It seems to me that a roof that emits more radiation will have a greater
> warming effect on the building. Some houses in warm climates have 
radiant
> barriers because the aluminum has a low emissivity, thus blocking the
> infrared radiation. But both LEED and Energy Star suggest high 
emissivity
> for warm climates. Does this make sense?
>
> From LEED NC Reference Guide v. 2.2:
>
> "To maximize energy savings and minimize heat island effects, materials
must
> exhibit a high reflectivity and a high emissivity over the life of the
> product."
>
> >From Energy Star website:
>
> "In warm and sunny climates highly emissive roof products can help 
reduce
> the cooling load on the building by releasing the remaining heat 
absorbed
> from the sun."
>
> Thanks,
>
> Brad
>
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