[Equest-users] HIR-FPLR

Doug Laney dlaney at geo-marine.com
Thu Jul 17 14:13:44 PDT 2008


If you haven't done so already, I'd recommend downloading the PDF files from
the DOE2 website.  It is the source of information for the help available in
equest, so there isn't much in the way of new information; however, I find
that being able to see the information in context of the section sometimes
helps me to figure out where my errors are coming from.


In this case, though, what equest is doing is determining your part load
ratio (PLR) as your current load divided by your specified capacity.
Assuming that you have used your peak efficiency to determine your HIR, then
Z should a quadratic function of PLR that will be multiplied by the HIR you
input.  Essentially, it is a penalty function that decreases the efficiency
of your equipment for not running at optimal load (which may or may not be
100%).  I hope this helps answer your question.





From: equest-users-bounces at lists.onebuilding.org
[mailto:equest-users-bounces at lists.onebuilding.org] On Behalf Of Brian Tysoe
Sent: Thursday, July 17, 2008 11:55 AM
To: equest-users at lists.onebuilding.org
Subject: [Equest-users] HIR-FPLR




I am looking at performance curves for Boilers in eQUEST, specifically Heat
Input Ratio as a function of Part Load Ratio, HIR-FPLR. Can anyone please
explain to me exactly how this works?


The curve has the form Z=a+bX+cX^2, where X is the part load ratio.
According to the help files Z "modifies the fuel consumption". In what way
does Z modify HIR?


Is HIR(X) equal to Full Load HIR divided by Z(X)?





Brian Tysoe M.Sc., LEED AP 


 <http://www.mcw.com> MCW Consultants Ltd. 

600-156 Front Street West 
Toronto, ON M5J 2L6 
Phone 416-598-2920 
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