[Equest-users] fishpond

Michael Wilson mwilson at enerficiency.ca
Thu May 3 16:06:05 PDT 2012


It depends on the temperature and RH in the room and the pool temp. If the
pool temp is higher than the room temp, it will always evaporate water into
the air, regardless of RH. If the air temp is higher than the pool temp,
then at a certain temp and RH water will condense from the air into the
pool. The dryer the air, the warmer the room temp will need to be before
that happens. At 100% RH it will occur as soon as the air temp exceeds the
room temp.

 

Mike

 

 

Michael Wilson, P.Eng., Enerficiency Consulting

PO Box 1911 - 458 Abbs Rd., Gibsons, BC  V0N 1V0    |    604-886-9864    |
www.enerficiency.ca

 

From: equest-users-bounces at lists.onebuilding.org
[mailto:equest-users-bounces at lists.onebuilding.org] On Behalf Of Ery
Djunaedy
Sent: May-03-12 2:52 PM
To: equest-users at lists.onebuilding.org
Subject: Re: [Equest-users] fishpond

 

Folks,

A side issue on the same topic.

I have gone through some literature on this topic. All the calculation
methods that I found are actually methods to calculate evaporation rate from
the pool with the ultimate goal to calculate (a) the heating load to
maintain the water temperature and (b) the latent load for the air above the
water. The underlying assumption used in all methods is that all the
evaporation heat is taken from the water (and nothing from the air).

I investigated this matter because I want to quantify the cooling effect of
an indoor pool to a naturally ventilated room. If I used the calculation
methods from the literature that I found (including Shah method below) what
I end up with is a latent load and a sensible load (both positive into the
zone) that will be added to the room, simply because the method assumes that
all the evaporation heat comes from the water (and nothing from the air).

I found this very hard to swallow because we all know for a fact that people
in hot climate use pools to cool down the indoor temperature. I am not
talking about fountain or sprayer, which has a totally different cooling
mechanism where all of the evaporation heat comes from the air. I am talking
about pools, either indoor pool or pools surrounding the building.

Is there any literature out there on the cooling effect of pools?

Thanks,

Ery



On 05/03/2012 09:32 AM, Bishop, Bill wrote: 

Cristian,

 

You can model it but you will need to calculate the latent and sensible
loads yourself, at least if you are using eQUEST. Without having experience
with fishponds, I would approach it like a natatorium (indoor swimming pool)
and use the ASHRAE Handbook – HVAC Applications Chapter 5 for design
guidance and loads calculations. Also, see this article:
http://hpac.com/humidification-dehumidification/simplified-calculating-evapo
ration-1011/ for alternate method of calculating evaporation loads. Based on
your drawings, I would also research state-of-the-art for aquaculture
facilities, as that looks to be what you are designing.

 

Regards,

Bill

 

 <mailto:wbishop at pathfinder-ea.com> 

 

 

From: equest-users-bounces at lists.onebuilding.org
[mailto:equest-users-bounces at lists.onebuilding.org] On Behalf Of Cristian
Salvador Jara Toro
Sent: Thursday, May 03, 2012 11:15 AM
To: equest-users at lists.onebuilding.org
Subject: Re: [Equest-users] fishpond

 

Sorry, but I meant "design" instead of "model"... because I don´t think to
model a room with water in it be possible...

On Thu, May 3, 2012 at 10:53 AM, Cristian Salvador Jara Toro
<cristian.jara.toro at gmail.com> wrote:

Greetings!

I have to model a room with a fishpond (more like close to a several
fountains where fishes will be inside). WxLxH=9x13x2.5 in meters.
Has anybody modeled something like that? 

So, what I need to know is about ventilation rates for a room like that,
wich contains water and fishes swimming in it, but my worry is about
condensations, so if anybody has some paper or standard, please let me know.

Thanks in advance...

-- 
Cristian Jara Toro
Cel: 6 207 8566







-- 
Cristian Jara Toro
Cel: 6 207 8566









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