[Bldg-sim] Custum curves

Sanjay संजय Cholekar cholekar at gmail.com
Wed Jul 27 01:49:12 PDT 2011

A resistance heater, converting 100% of its input electricity to output heat
would have a *3.41214 EER* (COP = 1), due to the fact that it takes about
0.293071 watt hours <http://en.wikipedia.org/wiki/Watt_hours> to equal one
BTU <http://en.wikipedia.org/wiki/BTU>.
Take* EER = COP x 3.412*

These curves are better explained in iesVE Software.

Sanjay Cholekar

On Sat, Jul 9, 2011 at 7:19 PM, sambhav tiwari <tiwari.sambhav at gmail.com>wrote:

> Hi All,
>         I created a custum curve for  DX system EIR=F(PLR)
> Now as per doe2 manuual it is said that when we enter PLR say 0.9
> itgives EIR as Power inputat (90Load/Power at full ie 100load)  so
> like this  i had four values of part load at 0.7 .8 .9 and 1 and i
> calculated the corrosponding EIR as Power at that load/full load power
> and my EIR at different  load 0.7 ,0.8, 0.9 and 1 was0.5968,
> 0.7193,0.8537 and 1 respectively based on this values i created a
> cubic curve for EIR as F(PLR)  but after making the custum curve my
> cooling energy in end results is going up by 15% i dont know as far as
> i think it should go down because at part load power consumption is
> less.
> So should  i enter EIR= as 1/cop at given load ,not as KWat given
> load/Kw at full load.
> Please give me some response.
> Thanks
> Sambhav.
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