Thank you for your answer.
I don't understand this completely however. Do you mean that the shading layer
conductance k is just equal to lambda/t (with lambda the slat conductivity and
t the slat thickness)? I find it strange that the distance between the slats is
nowhere included in this, as well as width of the slats (and equivalent shading
layer).
I was thinking that the conductance would have to be calculated somewhat like
this:
k=lambda/((t/(h+t))*w)
so that:
- for slats with no thickness, the conductance would be infinite (because there
is no material)
- for h=0 (no distance between slats), the conductivity of the shading layer
would be equal to the slat confuctivity, so that k=lambda/w
Can you tell me if I'm right or not?
Thanks in advance,
Thomas
--- In EnergyPlus_Support@yahoogroups.com,
"Griffith,
Brent" <brent.griffith@...> wrote:
>
> Blind layer conductance is calculated by dividing slat conductivity by
> slat thickness.
>
>
>
> ________________________________
>
> From: EnergyPlus_Support@yahoogroups.com
> [mailto:EnergyPlus_Support@yahoogroups.com]
On Behalf Of tboomgaert
> Sent: Friday, April 10, 2009 4:13 AM
> To: EnergyPlus_Support@yahoogroups.com
> Subject: [EnergyPlus_Support] Window blinds - conductance of shading
> layer in heat balance equations
>
>
>
>
>
>
>
>
> Hello,
>
> In the Engineering Reference on p.228-230 (heat balance equations for
> shading device and adjacent glass), it states that shading devices are
> treated as a uniform layer with a conductance k_sh.
>
> I was wondering how this k_sh is calculated for window blinds (with
> horizontal slats)? I can't seem to find anything on this in the
> engineering reference.
>
> Thanks in advance!
> Thomas
>