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[EnergyPlus_Support] Re: Cooling capacity to air flow ratio for splits



You are right. I confused.


--- In EnergyPlus_Support@xxxxxxxxxxxxxxx, Richard Raustad <RRaustad@...> wrote:
>
> I am not sure I agree that the cooling capacity is 1000 W.
> 
>  From the web site:
> 
>   * Cooling Capacity 9.000 / 1.000 BTU/HoursW
>   * 9,6915 BTU / W Cooling EER
>   * 2,84 W/W Cooling EER
>   * Cooling Capacity 2.268 / 1.000 kcal/Hours
>   * Cooling Capacity 2,64 / 1.000 kW
>   * 1 Pts/Hours Moisture Removal
>   * 7 Air Circulation (Max, m³/min)
> 
>   * 930 Watts Power Consumption (Cooling)
> 
> If the EER is 9.6915 BTU/W, then the cooling capacity is 9.6915 * 930 or 
> 9013 BTU/hr or 2640 W.
> 
> It looks to me like the cooling capacity is 2.64 Watts PER 1000 watts of 
> input power (the input power is actually 930 W).
> 
> For the Rated Evaporator Fan Power Per Volume Flow Rate input field, you 
> need to use the fan power, not the total cooling power which is 
> compressor power (and probably fan power as well since this is a 
> terminal unit).
> 
> 
> On 5/24/2013 7:54 AM, FrancescoP wrote:
> > I have a question concerning the ratio W/(m^3/s) for DX cooling coils.
> > I'm considering a split-type air conditioner similar to this one:
> > http://www.samsung.com/latin_en/consumer/home-appliances/air-conditioners/split/AS09UBAXAP-spec
> > As you can see, the cooling capacity is equal to 1000 W while the maximum air circulation is 7 m^3/min = 0,12 m^3/s. Therefore the ratio field "Rated Evaporator Fan Power Per Volume Flow Rate" would be 8571 W/(m^3/s). The default value for the field "Rated Evaporator Fan Power Per Volume Flow Rate" of the object Coil:Cooling:DX:SingleSpeed is equal to 773,3 W/(m^3/s), less than one tenth. Is such a big difference normal? Are values of about 8500 W/(m^3/s) normal for splits?
> > Best Regards
> >
> >
> >
> >
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> 
> -- 
> Richard A. Raustad
> Senior Research Engineer
> Florida Solar Energy Center
> University of Central Florida
> 1679 Clearlake Road
> Cocoa, FL  32922-5703
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> 
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>




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