Replaced large 26MB PDF of paper with a much smaller3.7MB one,
courtesy of Jim Dirkes. Web location is the same:
www.whiteboxtechnologies.com/PAPERS/88_YJH_etal_Fdn_Model.pdf
Joe
Joe Huang
White Box Technologies, Inc.
346 Rheem Blvd., Suite 108D
Moraga CA 94556
yjhuang@xxxxxxxxxxxxxxxxxxxxxxxx
www.whiteboxtechnologies.com
(o) (925)388-0265
(c) (510)928-2683
"building energy simulations at your fingertips"
On 4/29/2013 11:34 AM, Joe Huang wrote:
Jean,
My only comment is that I've always modeled the slab as carpeted.
Therefore, the foundation layer always starts with a carpet (or
what a colleague used to call "RUGNPAD" :-) ) that's modeled as a
pure resistance layer of R-1.08 (in IP). This doesn't affect the
total R-value of the modeled slab, just reduces the R-value of the
fictitious soil layer, but it does have an important effect in
decoupling somewhat the thermal mass of the concrete from the room
heat balance, which is the effect of the carpet.
For anyone interested, I've just scanned the old 1988 ASHRAE paper
("Whole-House Simulation of Foundation Heat Flows Using the
DOE-2.1C Program", by Huang, Y.J., L. Shen, J. Bull, and L.
Goldberg) and put it on the Web (www.whiteboxtechnologies.com/PAPERS/88_YJH_etal_Fdn_Model.pdf)
because it was the technical basis for the Winklemann article.
Please notice that the analysis, which was done for the Building
Foundation Design Handbook ( Labs et al., Univ. of Minn
Underground Space Center, 1988 now out of print), directly
imported the heat flows from the 2-D foundation model into the
DOE-2.1C simulations, similar to using the Slab program with
EnergyPlus. The U-effectives (or F Factors) were calculated for
two purposes: (1) to adjust the foundation heat flows for the
actual space temperature, and (2) to give readers a rough idea of
the net difference in heat flows between the 88 foundation
measures. I never thought of them as a stand-alone calculation
method, so it's been quite surprising to find them still
referenced 25 years later. Warning: the PDF is quite large (over
26MB) because it was all scanned.
Joe
Joe Huang
White Box Technologies, Inc.
346 Rheem Blvd., Suite 108D
Moraga CA 94556
yjhuang@xxxxxxxxxxxxxxxxxxxxxxxx
www.whiteboxtechnologies.com
(o) (925)388-0265
(c) (510)928-2683
"building energy simulations at your fingertips"
On 4/29/2013 3:36 AM, Jean Marais wrote:
My goal is to reverse engineer an
equivalent slab-on-grade construction for
simulations as per ASHRAE 90.1 Appx G.
F * Pexp = Ueff * A
= 1/Reff * A
This gives
Reff = A / (F * Pexp)...the user inputs
...therefor for a insulation rating
value that matches the standard's rated
insulation requirement for the required
F-factor and
substituting for the construction build up as
defined by ASHRAE 90.1 A6
Reff = Rairfilm_in + Rconcreate +
Rrequired_rated_insulation + Rsoil + Rother +
Rairfilm_out
where
*********************************
Rairfilm_in = 0.77 hr-ft2-F/Btu (0.14 m2-K/W)
is the average of the air film resistance for heat
flow up 0.61 hr-ft2-F/Btu (0.11 m2-K/W) and heat
flow down 0.92 hr-ft2-F/Btu (0.16 m2-K/W), as per
ASHRAE 90.1 A9.1.4 and Winkelmann
*************************************
Rconcreate = 0.07 m²K /W
as per ASHRAE 90.1 A6 for 0.5ft (150 mm)
concrete from ASHRAE 90.1 Table A3.1B, and density
2304 kg/m³
**********************************
Rrequired_rated_insulation can be found by
fitting a curve through the values in standard 90.1
Table A6.3 for fully insulated slab-on-grade:
ASHRAE 90.1 F-Factors for fully
insulated slabs and Unheated as per Appendix G
|
|
|
|
|
|
|
|
|
SI Units |
|
|
|
|
|
|
|
|
|
|
|
|
|
R-values |
0 |
0.9 |
1.3 |
1.8 |
2.6 |
3.5 |
4.4 |
5.3 |
6.2 |
7 |
7.9 |
8.8 |
9.7 |
F-factors |
na |
0.8 |
0.71 |
0.62 |
0.52 |
0.45 |
0.4 |
0.37 |
0.34 |
0.32 |
0.3 |
0.29 |
0.28 |
we can find the curve fit equation as
Rrequired_rated_insulation = 0.6065 *
( F )-2.165
****************************************
Rsoil is assumed 1 ft (0.3 m) at k=1.3 W/m²-K as
per Table A9.4D, which corrisponds to recommendations
in UNDERGROUND SURFACES: HOW TO GET A BETTER
UNDERGROUND SURFACE HEAT TRANSFER CALCULATION IN
DOE-2.1E, Winkelmann
therefore
Rsoil = 0.22 m²K /W
**************************************
Rairfilm_out = 0.0299387 m²K /W as per ASHRAE 90.1
A9.4.1
*************************************
Therefore the only unknown, Rother can be
calculated.
Rother = A / (F * Pexp) - (0.14) - (0.07)
- (0.6065 * ( F )-2.165)
- (0.22) - (0.0299387)
it is assumed Rother has material properties for
density and specific heat, the same as that of soil.
xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
Now I can build up an equivalent construction for
the "slab" espectially honed to exclusively
"slab-on-grade" for Appendix G of ASHRAE 90.1. If
Rother is negative, Rrequired_rated_insulation must be
"derated" to effect the difference. See the
spreadsheet attatched.
Thanks for all the help.
Jean.
PS other material properties one can use to build
up this construction in e+ could be as follows
Concrete |
150 mm |
Construction as per A6.1: |
|
|
|
|
|
Properties as per A3.1B for 150
mm, 2304 kg/m³ --> Rc = 0.07, HC = 294
--> |
|
|
specific heat = |
850.694444 |
J/kg-K |
|
|
|
|
Insulation R- |
|
0.36521482 |
m²K/W |
|
|
|
|
|
Properties as per HOF Expanded
Polystyrene extruded smooth skin 40 kg/m³,
0.030 W/m²-K |
|
thickness = |
0.01095644 |
mm |
|
|
|
|
Soil |
to account for thermal mass
effects of the soil as per DOE-2 Articles from
the Building Energy Simulation User News,
January 2003 and ASHRAE 90.1 table A9.4D |
|
|
|
k = |
1.3 |
W/m²-K |
|
|
|
|
|
thickness = |
0.3 |
m |
|
|
|
|
|
density = |
1840 |
kg/m³ |
as per DOE-2 referenced above |
|
On 29 April 2013 10:19, Joe Huang <yjhuang@xxxxxxxxxxxxxxxxxxxxxxxx>
wrote:
Jean,
My comments follow your questions below.
On 4/29/2013 12:05 AM, Jean Marais wrote:
Hi Joe,
I'm not getting any
further on this issue.
Perhaps you can lend
me some insight. You
say that the F-factors
in standard 90.1 were
the result of
parametric simulations
that you ran for
different
configurations of
perimeter
insulation...so let me
see if I understand
this right.
1) your model (1988)
assumed the walls were
Adiabatic so that only
the heat loss through
the slab-on-grade was
captured
No, the 2-D simulations I did were with a
finite-difference program for a vertical 1 ft.
slice through the foundation extending 15 ft
into the building.
In the original analysis done for the Foundation
Design Handbook in 1988, I multiplied the heat
flow of each FD element by the annulus length of
a 1540-ft2 house (55 ft x 28 ft) to derive the
total heat flow through the foundation. For the
simpler method described in Winklemann and
Huang,
I took the total heat flows across the entire
15 ft foundation slice and divided that by
temperature difference (Tin - Tout) to derive
the F-Factors per lineal foot of perimeter.
This actually overestimates the heat flows due
to the core section, but is a lot easier to
calculate. So, I repeat - no heat losses
are being ignored, just that their magnitude is
assumed to be a function of the perimeter
length.
2) you considered
vertical, horizontal AND
fully insulated
configurations
I did 88 foundation configurations for slab on
grade, 8' full basements, 4' half basements, and
ventilated crawl spaces. Slab configurations
include two depths of vertical perimeter edge
insulation (2' and 4') either R-5, R-10, or
R-15, on the outside or inside of the slab, and
also combinations of vertical and horizontal
extending down 2' and out 2' (this turned out to
be the most effective, as it decoupled more of
the soil from the outside air temperatures).
Basement insulation is similar, 4' 8' insulation
outside, inside, and integral (for a wood frame
foundation), crawl space configurations are
similar to the slab configurations. I think all
88 cases are described in both the 88 ASHRAE
paper as well as the Winkelmann Huang paper.
3) you used a 2D slab
simulation program
Yes, it was a 2-D finite difference program
written by Lester Shen at the Univ. of Minnesota
Underground Space Center. We did 5 years of
initialization, 4 on a monthly time step, 1 on a
daily time step, followed then by one year on a
daily timestep. The program was very robust, no
problems at all.
4) what inside air film
resistance did you use?
You have to distinguish the air film resistances
used in the 2-D simulations, and the ones used
in the whole building simulation incorporating
the 2-D results. I think we used pretty standard
ASHRAE values for the air film, maybe 0.77
Btu/hr-ft2-F . This actually gets rather
academic because the total effective R-value of
the foundation including the soil is quite high,
R-20 to R-40, especially when "coupled" with the
outside air temperature.
5) what outside air film
resistance did you use?
I believe it was a constant 0.17 Btu/hr-ft2-F in
the 2-D simulation, but in the whole house
simulation, this varied depending on wind speed.
Not a big effect.
6) what inside temperature did
you use?
Same caveat applies here. In the 2-D simulation,
Tin was constant 74F for the slab, lower for the
basement and crawl space, either 60 F or 65F.
In the DOE-2 simulation, the zone temperature
varies quite a bit, for which DOE-2 does a UA
delta T correction using the same F-Factor. This
adjustment was
especially large for the basement and crawl
space, and Lester and I came up with a crude
response factor to take into account the thermal
lag due to the large amount of thermal mass.
That was written up in the 1988 paper, but I did
not emphasize it in the simpler models.
7) what outside temperature did you
use? If it varied over time, how is it
that the F-factor can be constant? If
it varied by Climate Zone, R-value, or
other, could you tell me the
breakdown?
The outside temperature is the daily outdoor air
temperature. There's also a constant deep
ground temperature 50 ' down in the model.
Think of the F-Factor as a conductance, so it
scales with the temperature difference (Tin -
Tout). It's the crudest first-order
approximation because it doesn't take
the thermal lag of the soil into account, nor
does it distinguish between the temperatures of
the air, ground, and deep ground. What I did
were linear
regressions of the heat flux through the
foundation against the instantaneous temperature
difference Tin - Tout, averaged for 12 different
climates.
That was why when I did the project for the
Energy Commission a decade later, I split the
foundation into different domains and did
separate regressions for 3-week air temperature,
5' ground temperature, and deep ground constant
temperature.
On 25 April 2013 12:09, Joe Huang <yjhuang@xxxxxxxxxxxxxxxxxxxxxxxx>
wrote:
Jean, others,
It was quite a surprise to read
your e-mail and find that the old
F-Factors that I calculated back
in 1988 are still being referred
to in Standard 90.1. If you're
interested in more details of that
effort, there's an ASHRAE
Transaction paper
Huang, Y.J., L.S. Shen,
J.C. Bull, and L.F. Goldberg
1988. "Whole-house simulation
of foundation heat-flows using
the DOE-2 program",
ASHRAE Transactions,
Vol. 94-2.
and a 1998 User News
article written by Fred
Winkelmann on its
implementation in DOE-2 (see
attached).
The F-Factors are per
lineal feet of perimeter from
Tout to Tin of the space
containing the foundation.
There are actually several
ways to implement this model:
(1) model a monolithic
foundation as an exterior wall
and adjust the R-value of the
layer so that U*A = F*PL
(Perimeter length) -- this is
the method shown in the
Winkelmann article, (2)
decompose the foundation into
two regions - a perimeter
strip 1-2 ft wide and a core
for the remainder; model the
perimeter as an exterior wall,
adjusting its R-value
accordingly, but model the
core as an adiabatic layer.
When I was working with DOE-2,
there was a practical problem
that layers can't be too thick
or the response factor would
fail, so I could only add at
most 2.5 ft of soil. I don't
know if EnergyPlus has similar
limitations. Ideally, you
would want to model as much
soil as possible to get the
thermal dampening effect.
The main deficiencies
with this technique are (1)
Tout is the outside air
temperature, (2) the
foundation is treated as a
single layer. I know there's
a temptation to model the
foundation as a underground
layer tied to the soil
temperature, but that would be
wrrong since the F-Factors are
calculated air-to-air.
In the late 90's
(1998-2000), I worked with
Fred Winkelmann and Vladimir
Bazjanac for the Calif. Energy
Commission to develop what I
think is a much better model
that is now the approved
method for Title-24. This
model uses a similar approach
as before, except instead of
a single F-Factor, there are
six Foundation Conductances
for two domains (perimeter and
core) and three heat flow
paths ("quick" to the outdoor
air temperature the past 3
weeks, "slow" to the monthly
ground temperature, and
"constant" to the deep ground
temperature). The model is not
only more accurate, but more
flexible for different
building conditions. If
anyone's interested in the
report, it's available at www.whiteboxtechnologies.com/downloads/00_02.YJH.CEC_Fdn_Model.pdf
If I have it in my
power, I would urge everyone
to stop using the 1988 model
and switch to the 2000 model,
but since the F-Factors seem
to have been institutionalized
by now, that would be
irresponsible. So, I'll be
happy to answer questions
about the use of either model.
Joe
Joe Huang
White Box Technologies, Inc.
346 Rheem Blvd., Suite 108D
Moraga CA 94556
yjhuang@xxxxxxxxxxxxxxxxxxxxxxxx
www.whiteboxtechnologies.com
(o) (925)388-0265
(c) (510)928-2683
"building energy simulations at your fingertips"
On 4/24/2013 9:34 PM, Jean
marais wrote:
Dear Group,
e+ has a documented
technique of
converting the user
inputs of F-Factor,
Area and Perimeter
into a Equivalent
U-Value Contruction.
It seams however
that ASHRAE 90.1 and
HOF has too little
information on how
the F-Factors in
standard 90.1 were
created (for
example, which T_in
and T_out were used,
how were losses into
the soil accounted
for, which air film
resistances were
used, etc.) for me
to trust this
technique as a
compliance tool.
I propose the
following solution:
Baseline case...
In a nut shell, a
curve fit for the
"fully insulated"
case of the F-factor
table in
90.1...R-insulation
is then a function
of F-factor input.
Thus an equivalent
construction can be
created that
satisfies the
Standard in terms of
Rated R-insulation
covering the entire
slab, concrete
thickness and soil
conductivity as per
the description in
Appx A. As Dr Huang
suggested, use a 0.3
(also noted for this
thickness at the
back of 90.1 appx A)
at the soil
conductivity
perscribed by 90.1
to catch the thermal
mass effects of the
soil.
As a check, a
construction defined
in this way can be
looked up for its
F-factor and should
give the right
R-value using
interpolation.
Proposed case...
1) look at the
actual design
2) deturmin the
F-factor from Table
A6.3
3) Calculate
equivalent slab
construction as for
Baseline case using
the F-factor from
step 2)
It should be said
that if your slab
does not meet the
criteria for
"slab-on-grade" as
per 90.1, then the
standard has no
requirement of it
and it should be
modelled identically
to that of the
proposed case model
(e.g. Basement slabs
are not
slab-on-grade)
Your comments
please, after
reading some of the
rest of these
corrispondances.
Kind regards,
Jean
Further reading...
I would like to draw
your attention to
how COMcheck
software handles
slab-on-grade
F-factors.
http://www.energycodes.gov/sites/default/files/documents/BECP_Technical%20Support%20Document%20for%20Version%20391%20of%20the%20COMcheck%20Software_Sept2012_v00.pdf
Another interesting
take is that of DOE2
http://simulationresearch.lbl.gov/dirpubs/un_articles02.pdf
The tabled F-factors
here were deturmined
by Huang using 2D
parametric
studies...the
tabulated values
don't match those in
ASHRAE 90.1. See the
onebuilding forum
note by Joe Huang http://www.gard.com/ml/bldg-sim-archive/msg01047.html
Comments, please.
Kind regards,
Jean Marais
On 19 April 2013
16:59, Tianzhen Hong
<thong@xxxxxxx> wrote:
Jean,
When we developed
this feature for
EnergyPlus, we did
quite some research
on the topic and you
also pointed out,
ASHRAE did not have
every details on
F-factor. A few
years back, I was
developing EnvStd, a
tool used for ASHRAE
90.1 envelope
tradeoff, F-factor
was used to
calculate the
equivalent heat
transfer between the
zone and outdoor,
there is no such a
term of "heat flow
into soil
environment".
Tianzhen
On Fri, Apr 19, 2013
at 2:32 AM, Jean
Marais <jeannieboef@xxxxxxxxx>
wrote:
HOF 18.31 equation
41 with equation 42
for "at grade
surfaces" can be
combined as follows:
q = Pexp*F*delta_t
...unfortuanately
delta_t is not
defined
here...judging from
the previous section
for slabs below
grade, I must
currently assume
delta_t = (T_in -
T_ground), though
for perimeter losses
delta_t = (T_in -
T_ODA) may be more
appropriate.
In context of slabs
below grade, I see
that the for heat to
travel from T_in to
T_ground, it must
travers Rfilm_in,
Rcon, Rinsulation
(if any) and
possibly a
R_soil_to_slab
(probably
negligable).
However, for slabs
at grade the heat
travels partly into
the ground and
partly into the ODA
via the ground. i.e.
I could assume that
the F-factors were
calculated somewhat
as below:
qtot = heat flow
into soil
environment + heat
flow into outdoor
environment through
perimeter effects
= [Area *
U_slabconstructionwithinteriorairfilmresistances
* (T_in - T_ground)]
+ [Pexp * F * (T_in
- T_ODA)]
= [Area /
(Rfilm_in+Rcon+Rins)
* (T_in - T_ground)]
+ [Pexp /
(Rfilm_in+Rcon+Rins+Rsoil_path_to_outdoors+Rvertical_insulation+Rfilm_out)
* (T_in - T_ODA)]
...there is a small
overlap here, but
should be
negligable.
As you can see, if
this is the case,it
is very important to
establish what
Rsoil_path_to_outdoors
was used for the
F-factor ratings in
90.1. Alternatively,
1) soil conductivity
used for the
F-factor ratings in
90.1 = 1.30 W/m-K as
per A6.1
2) soil heat flow
path length for the
F-factor ratings in
90.1...can be
assumed the distance
of the corrisponding
F-factor insulation
and type. E.g.
F-0.90 corrisponds
to R-1.8 and 600 mm
vertical insulation,
which approximates a
soil travel path of
2x600 mm.
HOF does not mention
any air film
resistances in
chapter 18.31, but
90.1 lists these for
rating values in
A9.4.1. Assuming an
average for heat
flow up and down is
probably a good
approximation for
the interior air
film resistances as
the temperature of
the soil cycles over
the annual average
for half the year
and under the
average for the
other half
(sinusoidal).
The values in HOF
table 24 are in the
same range as those
in 90.1 table A6.3.
Furthermore, HOF
equation 42 defines
q = heat loss
through
perimeter...this
leads me to believe
that the F-factor
rating values in
90.1 express only
heat losses of
perimeter effects
and does not include
those to the soil.
In summary:
INPUT VALUES
F-factor
Pexp
Area
T_ground =
anual_mean_ground_temperature
used for the
F-factor rating
values is assumed at
0.3 m...0.3 from
Winkelmann's
slab-on-grade
model...we assume
the rating values of
90.1 included
variation per
climate zone and
that this
corrisponds to user
input.
T_in =
anual_mean_indoor_temperature
used for the
F-factor rating
values is assumed to
have been assumed at
20ºC for conditioned
spaces
T_ODA =
annual_mean_outdoor_temperature
...it is assumed
that the F-factor
rating values had
assumed the
annual_mean_outdoor_temperature
for calculation and
that climate zone
variation was taken
into account. It is
assumed this
temperature will
closely match the
user input.
GIVEN / ASSUMED
VALUES
Rcon = 0.077 m2-K/W
...as in EngRef
which co-insides
closely to values in
90.1 Table A3.1B
Rfilm_in = 0.14
m2·K/W ...which is
the average of the
0.11 m2·K/W for heat
flow up and 0.17
m2·K/W for heat flow
down as per 90.1
A9.4.1...this
differs from EngRef!
Rfilm_out = 0.03 ...
as per EngRef and
90.1 A9.4.1 for all
exterior facing up
or sideways
surfaces...NB not
for external floors
k_soil = 1.30 W/m-K
...as per A6.1
LOOKUP VALUES
Insulation_configuration_best_fit_for_F-factor_from_Table_A6.3
(Perimeter_Insulation_is_Vertical,
Ins_mm, R-value)
CALCULATED VALUES
Soil_Heat_Flow_Path_Length
Rins
the rest
Someone may shed
some more light on
how the rating
values were
calculated so that
we can back
calculate the
U-value of the slab
construction.
Kind regards,
Jean.
On 19 April 2013
08:50, Jean Marais
<jeannieboef@xxxxxxxxx>
wrote:
Thanks Mike, I will
check the handbook
and see if revers
calculatiosn can
bring some light.
Funny thing that
definition...the
definition is aimed
at slabs that lay
exposed above the
grade line and are
exposed to the OD
environment (that
means that their is
no requirement for
basement slabs!,
i.e. for basement
slabs the baseline
is modeled as
proposed case), but
includes "or is less
than or equal to 600
mmj below the final
elevation of the
nearest exterior
grade".
If I learn anything
more, I'll post it.
Kind regards,
Jean.
On 18 April 2013
17:46, Michael J
Witte <mjwitte@xxxxxxxx> wrote:
Jean:
Just to clarify, for
"slab-on-grade" the
slab edge is exposed
to the air (directly
or through
insulation). From
Std. 90.1 Appendix
A, section A6.1 "For
the purpose of
Section A1.2, the
base assembly is a
slab floor of 6 in.
concrete poured
directly on to the
earth, the bottom of
the slab is at grade
line, . . ."
It seems there are
several issues here.
1. How to convert
from F-factor to
equivalent U-value.
This is what your
users need to know,
regardless of how
F-factor has been
implemented or
documented in
EnergyPlus. There
appears to be some
guidance here, but I
do not have access
to my handbook at
the moment to check
this:
http://lists.onebuilding.org/pipermail/equest-users-onebuilding.org/2010-March/003573.html
2. The second issue
is whether
EnergyPlus has
implemented and
documented the
f-factor model as
intended. I don't
have the answer to
that at the moment.
What I can tell you
is that the source
code matches the
v8.0 documentation.
It creates two
material layers
(which you should be
able to report in
the eio output using
Output:Constructions).
Concrete layer
(inside layer):
! Add the 6" heavy
concrete for
constructions
defined with F or C
factor method
IF
(TotFfactorConstructs
+
TotCfactorConstructs
>=1 ) THEN
MaterNum =
MaterNum + 1
Material(MaterNum)%Group=RegularMaterial
Material(MaterNum)%Name
= '~FC_Concrete'
Material(MaterNum)%Thickness
= 0.15d0 ! m,
0.15m = 6 inches
Material(MaterNum)%Conductivity
= 1.95d0 !
W/mK
Material(MaterNum)%Density
= 2240.0d0 !
kg/m3
Material(MaterNum)%SpecHeat
= 900.0d0 !
J/kgK
Material(MaterNum)%Roughness
= MediumRough
Material(MaterNum)%AbsorpSolar
= 0.7d0
Material(MaterNum)%AbsorpThermal
= 0.9d0
Material(MaterNum)%AbsorpVisible
= 0.7d0
NominalR(MaterNum) =
Material(MaterNum)%Thickness
/
Material(MaterNum)%Conductivity
Material(MaterNum)%Resistance
= NominalR(MaterNum)
Rcon =
Material(iFCConcreteLayer)%Resistance
The second layer is
the insulation layer
(outside layer) with
Rfic:
Reff = Area /
(PerimeterExposed *
Ffactor) - Rfilm_in
- Rfilm_out
Rfic = Reff -
Rcon
! ASHRAE Handbook
Fundamental 2005
!Thermal
resistance of the
inside air film,
m2.K/W. Average of
0.14 (heat flow up)
and 0.11 (heat flow
down)
REAL(r64),PARAMETER
:: Rfilm_in =
0.125d0
!Thermal
resistance of the
outside air film
used in calculating
the Ffactor, m2.K/W.
0.17/5.678
REAL(r64),PARAMETER
:: Rfilm_out =
0.03d0
Looking at example
file
1ZoneUncontrolled_FCfactor_Slab_UGWall.idf
Construction:FfactorGroundFloor,
slabconst,
!- Name
0.12,
!- F-Factor {W/m-K}
232.26,
!- Area {m2}
61.0;
!- PerimeterExposed
{m}
! <Material CTF
Summary>,Material
Name,Thickness
{m},Conductivity
{w/m-K},Density
{kg/m3},Specific
Heat
{J/kg-K},ThermalResistance
{m2-K/w}
Material CTF
Summary,~FC_Insulation_1,
0.0000,
0.000,
0.000,
0.000, 31.50
Material CTF
Summary,~FC_Concrete,
0.1500,
1.950,
2240.000,
900.000, 0.7692E-01
When the Ffactor
surface heat balance
is done, the inside
convection
coefficient is
varying as it does
for any surface in
EnergyPlus. This
seems reasonable.
However, the outside
surface temperature
is set directly to
the current value
of
Site:GroundTemperature:FCfactorMethod,
so there is no
outside film
coefficient
resistance during
the simulation.
This makes me
question whether
Rfilm_out should be
dropped from this
equation:
Reff = Area /
(PerimeterExposed *
Ffactor) - Rfilm_in
- Rfilm_out
And as you ask,
where did the values
for Rfilm_in and
Rfilm_out come
from? Do they match
the ASHRAE f-factor
calculations.
3. Finally, is the
DesignBuilder team
planning to
implement the F and
C-factor option?
Mike
On 4/18/2013 1:08
AM, Jean Marais
wrote:
Hi Linda,
Mr. Hong is not
responding...
Sorry. This issue is
not going away. As
stated, yes, the
documentation has
changed in v8, but
still refers to air
on the outside of
the slab and no soil
is mentioned, i.e.
"Q = Area * Ueff *
(Tair,out – Tair,in)
= (Tair,out –
Tair,in) * (Pexp *
F-factor)",
"Tair,out is the
outside air
temperature in °C",
"The outside air
film resistance
Rfilm, out = 0.03
m2·K/W.", etc.
If a slab is
"on-grade" then I
fail to see how
air_outside can
factor into the
equation. Mr. Hong
has insinuated that
these issues have
been corrected "The
air film (either
inside or outside)
is not included in
the calculation of
effective U-factor.
The soil layer is
modeled as part of
the 6" concrete and
an insulation layer
to come up with the
equivalent
U-factor.", but the
documentation of the
last v8 release does
not reflect it. As I
am supporting
DesignBuilder, and
DesignBuilder does
not currently
support the F-factor
objects for e+, it
is important for me
to explain to
clients how to
calculate the Ueff
to properly reflect
the f-factors in
90.1. No one has
been able to explain
this to me. I need
to know what R-soil
ASHRAE was using for
these f-factors AND
which film factors
(if any) are
included in the
f-ractor rating
values.
This information
would help many
users who have been
ignoring this issue
for many years. I'm
always supprised how
long people have
been "conforming" to
ASHRAE 90.1 for
simulations.
Kind regards,
Jean
On 17 April 2013
14:51, Linda Lawrie
<linda@xxxxxxxxxxxxxx> wrote:
I presume he meant
the current V8
release. But I'm
not sure.
At 11:21 PM
4/16/2013, jeannieboef@xxxxxxxxx wrote:
May I ask for your
source of
information? Do you
mean the next
release, as the v8
documentation
includes the film
resistances?
Kind regards,
Jean
Sent from my iPhone
On 16.04.2013, at
22:36, Tianzhen Hong
<thong@xxxxxxx> wrote:
Jean,
We clarified the
documentation in the
coming E+ 8.0
release.
The air film (either
inside or outside)
is not included in
the calculation of
effective U-factor.
The soil layer is
modeled as part of
the 6" concrete and
an insulation layer
to come up with the
equivalent U-factor.
Tianzhen
To: linda@xxxxxxxxxxxxxx
Subject: [EnergyPlus
!7333]: F-factor
method
engineeringreference
documentation error?
Date: Wed, 10 Apr
2013 09:39:30 +0000
Jean Marais updated
#7333
-------------------------
F-factor method
engineeringreference
documentation error?
---------------------------------------------------------
Ticket ID: 7333
URL: http://energyplus.helpserve.com/staff/Tickets/Ticket/View/7333
Full Name: Jean
Marais
Email: jeannieboef@xxxxxxxxx
Creator: User
Department: General
Staff (Owner): --
Unassigned --
Type: Issue
Status: Open
Priority: Medium
Template Group:
Default
Created: 10 April
2013 09:39 AM
Updated: 10 April
2013 09:39 AM
Due: 11 April 2013
09:39 AM (1d 0h 0m)
Resolution Due: 12
April 2013 09:39 AM
(2d 0h 0m)
Dear Team,
How can there be an
air-resistance-film
on the underside of
the slab? I am
comparing to DOE-2E
http://www-esl.tamu.edu/docs/terp/2012/ESL-TR-12-02-01.pdf
Surely a soil layer
should be assumed
here. And then which
soil layer was used
for the F-factors
listed in ASHRAE
90.1?
Please advise.
Kind regards,
Jean.
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