Thank you, Jim.
I am trying to understand the basic thermodynamics behind heat generation from an electric equipment. For instance, we provide X amount of heat to an equipment and part of this will be converted into work and another part into the heat. In my particular case, I have 2.2 MW of electric load inside a zone. Does it mean that this whole will be converted into heat or part of this. Please correct me if I am wrong.. Thanks again.
ÂJaved,Latent + Sensible + Lost = 1.0 ALWAYSFor electric equipment, it is possible to have latent (moisture) load; examples are a coffee pot and an electric humidifier.If your electric equipment generates moisture and has sensible heat ratio of 65%, then I think the latent fraction should be .35.On Mon, Mar 7, 2016 at 2:31 AM, Javed Iqbal eee.javed@xxxxxxxxx [EnergyPlus_Support] <EnergyPlus_Support@xxxxxxxxxxxxxxx> wrote:ÂHi,I am trying to simulate a internal equipment in a zone with a known sensible heat ratio that would be transferred to the zone air heat gain. I referred I/O reference file an found following are the three heat ratios types based on source type. In my case, Fraction latent and Fraction radiation is "0" as given in the specification sheet.  My question is what would be the correct value to simulate Sensible heat ratio of 65% in the following heat ratio objects?--â??Thanks,â??Javed Iqbal, LEED AP, CEASr. Energy AnalystÂ--James V Dirkes II, PE, BEMP, LEED AP
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